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360x-12x^2=0
a = -12; b = 360; c = 0;
Δ = b2-4ac
Δ = 3602-4·(-12)·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{129600}=360$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-360}{2*-12}=\frac{-720}{-24} =+30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+360}{2*-12}=\frac{0}{-24} =0 $
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